►Jump over to have practice at Khan academy: Integral test.arrow-up-right Refer to article from tkiryl: The Integral Testarrow-up-right Refer to Khan academy: Integral Testarrow-up-right
►Jump over to have practice at Khan academy: Integral test.
▼Refer to awesome article from xaktly: Integral Testarrow-up-right
Assume the series a𝖓 can be represented as a function f(x). There are a few limitations for it to use the Integral test:
a𝖓
f(x)
f(x) MUST BE continuous.
f(x) > 0. It MUST BE a positive function.
f(x) > 0
f'(x) < 0. It's MUST BE decreasing.
f'(x) < 0
Solve:
The Integral test has introduced the idea of calculating the total area under the function:
Integral test
The series has step of 1, which means Δx = 1
Δx = 1
We can sum the areas (which equals the series itself):
But when we are to INTEGRATE the function area under the function:
The dx is infinitely small rather than a fixed number Δx = 1.
dx
As result, the INTEGRAL is almost always greater than the SERIES AREAS.
As been said above, we got this conclusion:
Notice: DO NOT use the Integral Test to EVALUATE series, because in general they are NOT equal.
Integral Test
Last updated 7 years ago