Integral Calculus
Last updated
Last updated
Integral calculus is a process to calculate the AREA
between a function and the X-axis (or Y-axis).
Refer to Khan academy: Introduction to integral calculus
Riemann Sums
A Riemann sum is an approximation of the area under a curve by dividing it into multiple simple shapes (like rectangles or trapezoids).
Riemann Sums Notation
Refer to Khan academy: Definite integral as the limit of a Riemann sum
The letter ʃ
(reads as "esh" or just "integral") is called the Integral symbol/sign
.
Calculate Riemann Sums
Finding indices m & n
: It's meant to find the i
for Σ
sums:
For Left Sums
or Midpoint Sums
: i
starts from 0
ends with subdivisions - 1
For Right Sums
: i
starts from 1
ends with subdivisions
Finding xi
: With equally spaced points (left/right/mid), the xi
is a Geometric series
of those points, which the rate is the 𝚫x
. We're gonna find the right pattern/equation for xi
, so that we can plug xi
into f(x)
.
Finding f(xi)
: Just to plug in the Geometric series expression of xi
into f(x)
, and make it as a function in terms of i.
Refer to Maths is fun: Integral Approximations
Left Riemann Sum
: take the Left boundary value of Δx to be the rectangle's height.
Right Riemann Sum
: take the Right boundary value of Δx to be the rectangle's height.
As you can see, they would be either Over-estimated or Under-estimated. Neither of these approximations would be called a good one, normally.
It's an enhancement to the Left sums and Right sums, it takes the midpoint value, and sometimes makes better approximation.
It's easy to find the Δx=2
.
Then let's find the f(x𝖎)
. It's actually a progress to find the Arithmetic Sequence
.
So the sequnce is S(𝖎) = a + 𝖎·Δx = 2 + 2𝖎
, where a
represents the first x
value which is 2
.
So x𝖎 = S(𝖎) = 2+2𝖎
Takes it back to the function and gets: f(x𝖎) = |2+2i-5| = |2i -3|
How to calculate Riemann Sums
Refer to Khan academy: Rewriting definite integral as limit of Riemann sum
Finding 𝚫x
: It's meant to get HOW MANY rectangles we're to sum.
Solve:
Solve:
Solve:
Solve: