Calculus Basics
  • Introduction
  • ▶️Limit & Continuity
    • Limit properties & Limits of Combined Functions
    • Limits at infinity
    • All types of discontinuities
  • ▶️Differential Calculus
    • Differentiability
    • Local linearity & Linear approximation
    • Basic Differential Rules
    • Chain Rule
    • Derivatives of Trig functions
    • Implicit differentiation
    • Higher Order Derivatives
    • Derivative of Inverse functions
    • Derivative of exponential functions
    • Existence Theorems
    • L'Hopital's Rule
    • Critical points
      • Extrema: Maxima & Minima
      • Concavity
      • Inflection Point
    • Second Derivative Test
    • Anti-derivative
    • Analyze Function Behaviors with Derivatives
    • Optimization
    • Applications of Derivatives
      • Motion problems
      • Planar motion
  • ▶️Integral Calculus
    • Definite Integrals
    • Antiderivatives
    • Fundamental Theorem of Calculus (FTC)
    • Basic Integral Rules
    • Calculate Integrals
    • Integration using Trig identities
    • Improper Integral
    • U-substitution → Chain Rule
    • Integrate by Parts → Product Rule
    • Partial fractions → Log Rule
    • Trig-substitutions → Trig Rule
    • Average Value of Functions
  • ▶️Differential Equations
    • Parametric Equations Differentiation
    • Separable Differential Equations
    • Specific antiderivatives
    • Polar Curve Functions (Differential Calc))
    • Logistic Growth Model
    • Slope Field
    • Euler's Method
  • ▶️Applications of definite integrals
  • ▶️Series (Calculus)
    • Infinite Seires
    • Infinite Geometric Series
    • Convergence Tests
      • nth Term Test
      • Integral Test
      • p-series Test
      • Comparison Test
      • Ratio Test
      • Root Test
      • Alternating Series Test
    • Absolute vs. Conditional Convergence
      • Error Estimation of Alternating Series
      • Error Estimation Theorem
      • Interval of Convergence
    • Power Series
      • Taylor Series
      • Maclaurin Series
      • Lagrange Error Bound
      • Finding Taylor series for a function
      • Function as a Geometric Series
      • Maclaurin Series of Common functions
      • Euler's Formula & Euler's Identity
  • Multivariable functions
    • Parametric Functions
    • Partial derivatives
    • Gradient
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On this page
  • What is Implicit & Explicit Function
  • How to Differentiate Implicit function
  • How to differentiate Y with respect to X
  • How to differentiate term MIXED with both X & Y
  • Example
  • Example
  • Example
  • Example
  • Vertical & Horizontal Tangents of Implicit Equations
  • Example
  • Example
  1. Differential Calculus

Implicit differentiation

PreviousDerivatives of Trig functionsNextHigher Order Derivatives

Last updated 6 years ago

Bit hard to understand it in the first place.

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What is Implicit & Explicit Function

Refer to video by Krista King: What is implicit differentiation?

  • Explicit function: it's the normal function we've seen a lot before, which's in the form of y = x....

  • Implicit function: it't NOT YET in the general form of a function and not easily separated, like x² + y² = 1

So knowing how to differentiate an implicit function is quite helpful when we're dealing with those NOT EASILY SEPARATED functions.

How to Differentiate Implicit function

Refer to video: Use implicit differentiation to find the second derivative of y (y'') (KristaKingMath) Refer to video by The Organic Chemistry Tutor: Implicit Differentiation Explained - Product Rule, Quotient & Chain Rule - Calculus

Refer to Symbolab: Implicit Derivative Calculator

Assume you are to differentiate Y WITH RESPECT to X, written as dy/dx:

  • Differentiate terms with X as normal

  • Differentiate terms with Y as the same to X, BUT multiply by (dy/dx)

  • Differentiate terms MIXED with X & Y by using Product Rule, then differentiate each term.

How to differentiate Y with respect to X

How to differentiate term MIXED with both X & Y

Example

  • Treat y as y(x)

  • Apply the Sum Rule:

  • Apply the normal rules to X term, and

  • Apply the Product Rule to the Mixed term, and

  • Apply the Chain Rule to the Y term:

  • Operate the equation and solve for dy/dx, and get:

Example

  • First thing we need to find the RIGHT equation of Chain rule. Since it's asking us to find dy/dt, so we will re-write it to this one to form an equation:

  • Then since we've given the dx/dt = -3, we only need to find out the dy/dx to get the result.

  • We've got an equation of x & y, regardless whom it's respecting to. So we can do either Implicit or Explicit differentiation to the equation y²=7x+1, with respect to y:

  • Use the implicit differentiation method, we got the dy/dx = 7/2y

  • And since y=6, so 7/2y = 7/12

  • Back to the Chain Rule equation, we get dy/dt = 7/12 · (-3) = -7/4 = -1.75

Example

  • Remind you that, in this problem, it's NOT respecting to x anymore, so you need to change mind before getting confused.

  • First thing we need to find the RIGHT equation of Chain rule. Since it's asking us to find dx/dt, so we will re-write it to this one to form an equation:

  • Then since we've given the dy/dt = -0.5, we only need to find out the dx/dy to get the result.

  • We've got an equation of x & y, regardless whom it's respecting to. It seems easier to differentiate explicitly:

  • Then we use d/dx to differentiate the equation to get: dx/dy = y⁻² = (0.2)⁻² = 25

  • Back to the Chain Rule equation, we get dx/dt = dx/dy · dy/dt = 25 * (-0.5) = -12.5.

Example

  • Form an equation:

  • dx/dt has been given equals to 5, so just to find out dy/dx:

  • And get:

  • Now let's see what is sin(x) equal to:

  • All done.

Vertical & Horizontal Tangents of Implicit Equations

► Jump over to Khan academy for practice.

Example

  • Plug in y = 0 into the equation and get that x = -6, which is the answer.

Example

  • To have a Vertical Tangent, we have to let the derivative become Undefined,

  • which in this case is to let the denominator equal to zero:

  • Solve this equation out we get that x = 3y², which means this relationship is true at the point of vertical tangent line.

  • Plug that back to the original function to get y = -1, which means the vertical tangent goes through this point.

  • Substitute y back and get x = 3

  • The answer is (3, -1).

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Solve: Refer to Symbolab: Implicit Derivative Calculator

Solve:

Solve:

Solve (Same with above examples):

Solve:

Solve:

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