Slope Field
▶ Refer to Khan academy: Worked example: range of solution curve from slope field
![](https://solomons-mathbook.gitbook.io/~gitbook/image?url=https%3A%2F%2Fuser-images.githubusercontent.com%2F14041622%2F41281238-746b311a-6e63-11e8-8b36-997f706f2377.png&width=768&dpr=4&quality=100&sign=e3ff52ef&sv=1)
Example
Example
Solve: Hint: Try a point or points in each quadrant, like Q1: (2,2), Q2: (-2,2), Q3: (-2,-2), Q4: (2,-2)
Let's only try the point
(2, 2)
, we will gety' = 0
, which means the line in Q1 would be horizontal.
![](https://solomons-mathbook.gitbook.io/~gitbook/image?url=https%3A%2F%2Fuser-images.githubusercontent.com%2F14041622%2F41345924-920199ce-6f37-11e8-9ec1-0ee21bcf2dcf.png&width=768&dpr=4&quality=100&sign=38bb4226&sv=1)
Example
Since
6
is the initial condition, so we make6
as a boundary.The slope at
(0,6)
is a negative slope, which seems keeps negative until4
.So the Range would be
(4, 6]
.
Example
Try out a point, etc, the initial point is
(0, 1)
.TAKE DERIVATIVE of each equation, to get the SLOPE of each.
Plug in the
x=0
value to get each slope, and eyeball it.
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