# Applications of Derivatives

## Lose of bears

![image](https://user-images.githubusercontent.com/14041622/40659562-2f88308a-6381-11e8-8f0d-8c2253a56bb2.png) Solve:

* Just take the derivative `B'(t)` and input `t=2` to get the value `B'(2) ≈ -361 bears/year`.
